Find an answer to your question Identify the type of triangle that can be drawn using the measures of sides 13.5 cm, 5 cm, and 9.5 cm. With N as centre and 5 cm as radius, draw another arc on the same side of MN to intersect the former arc at L. 4. Whiat is… This site is using cookies under cookie policy. With each vertex of the triangle as centre, a circle is drawn with radius equal to half the length of the side of the triangle (see figure). !find the area of the shaded region​radius-- r this is re-upload of previous question because many were asking for r 1) Draw a line segment BC of length 5.5 cm. You can specify conditions of storing and accessing cookies in your browser. Construct an equilateral triangle with sides 5 cm and justify the construction. A Euclidean construction. With N as centre and 5 cm as radius, draw another arc on the same side of MN to intersect the former arc at L. 4. asked Nov 2, 2020 in Geometry by Darshee (49.0k points) geometry; class-9; 0 votes. That will result in two smaller right triangles. Construction : (i) Draw the ∆ABC with the given measurements. (i) Draw a line segment BC of length 5.5 cm. Taking 5.5 cm as radius, and A as center, draw an arc. The steps of construction are as follows. Since, all sides are equal , therefore, △ ABC is an equilateral triangle. (ii) Taking point B as centre, draw an arc of 5.5 cm radius. Call it AB. Draw a line segment MN = 5 cm. Marked X and Y on the line such that XY = 7.5 cm. Drop a perpendicular line from the 'peak' down to the base. (iii) Join AB and AC ∆ ABC is the required equilateral triangle, (iv) Draw the angle bisectors of ∠A, ∠B and ∠C. Join AB and AC. 2. 5%. ABC is the required equilateral triangle. Marked the point of intersection as Z. These are the lines of symmetry which are three in numbers as the triangle is equilateral. That will result in two smaller right triangles. Draw an equilateral triangle of sides 6.5 cm and locate its Orthocentre. Draw a circle of diameter of 9 cm. Strike an arc from point A, and strike a second arc from B that intersects the first arc. An equilateral triangle of side 5.5 cm has to be constructed. If you have any 1 known you can find the other 4 unknowns. Step 4: Mark the point where both these lines meet as C. CHECK. 5. Triangles by angle measure 4. Point charges are fixed to each corner, as shown. 1) Draw a line segment AB of length 5.5 cm. 2. 1. 3) Taking 5.5 cm as radius, and B as centre, draw another arc. The drawing shows an equilateral triangle, each side of which has a length of 3.50 cm. Create an equilateral triangle. 9 years ago. Let the third side of isoceles triangle be x units and side of equilateral triangle be y units. The steps of construction- Repeat with the other side of the line. An equilateral triangle of side 5.5 cm has to be constructed. This site is using cookies under cookie policy. Draw an equilateral triangle whose each side is 4.5 cm. Taking 5.5 cm as radius, and B as center, draw another … Ex 10.2, 2 Construct an equilateral triangle of side 5.5 cm. With A as a center and radius 5.5 cm, draw an arc. We know that all sides of an equilateral triangle are of equal length. The percentage increase is *​, 23-[3-2{7-(4-2+3)}]+17Their is a bar bracket in 2+3​. For equilateral triangles h = ha = hb = hc. A. 10%. Draw a line segment BC = 5 cm. Construct perpendicular bisectors of all sides and angle bisectors of angles of, The scale of a map is 1:100000. 3. Math Warehouse's popular online triangle calculator: Enter any valid combination of sides/angles(3 sides, 2 sides and an angle or 2 angle and a 1 side) , and our calculator will do the rest! If you have any 1 known you can find the other 4 unknowns. However, when constructing a perpendicular bisector it is necessary to make the arc at both sides of the line. Draw a line segment BC = 5 cm. Ex 10.2, 2 Construct an equilateral triangle of side 5.5 cm. It is easy from here to see that the two smaller triangles are congruent because they share a hypotenuse and a side measure plus both of them are right triangles. Classify the given triangles based on its sides as scalene, isosceles or equilateral. Triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. Draw a line segment BC of 5.5 cm. By construction, AB = AC = BC (Radius of equal arcs). Draw a straight line, and place the point of the compass on one end of the line, and swing an arc from that point to the other point of the line segment. Using the Pythagorean theorem, the altitude can be calculated. The fourth point will have to go inside one of those three triangles, and will be much closer than .5 cm to the vertexes of that triangle. Greater than or equal to 43 deg Equal to 43 degrees With C as the centre and a radius equal to 2.6 cm, draw an arc cutting the previously drawn arc at A. Bisect ∠ M of the triangle. Step 2: Using a protractor draw an angle of 60° from Point A. Take the largest angle and draw the angle bisector. 2) Taking point B as centre, draw an arc of 5.5 cm radius. Construction: Step 1: Drawn a line. (iv) ΔCAB is the required triangle. Find the area of the shaded region. It will even tell you if more than 1 triangle can be created. See Figure 3.8. Draw a line segment AB of length 5.5 cm 2. 1.Draw any line l. 2.Take any point M on it and draw a line p perpendicular to l. 3.With M as centre, cut off MC = 6 cm 4.At C, with initial line CM construct angles of measures 30° on both sides and let these lines intersect line l in A and B. Favorite Answer. 1) Draw a line segment BC of length 5.5 cm. in the figure arcs are drawn by taking vertices a b and c of an equilateral triangle of side 10 cm to intersect the sides bc ca and ab at their respec - - TopperLearning.com | m4kwt6myy The altitude shown h is hb or, the altitude of b. 1 answer. Sides of an equilateral triangle are all of equal length. Using ruler and compasses only, draw an equilateral triangle of side 4.5 cm and draw its circumscribed circle. Trace a quarter circle with the pencil end of the compass moving upwards, then switch the ends of the compass around. An isosceles triangle has 2 congruent sides. Construct an equilateral triangle with sides 5 cm and justify the construction. Solution for 18. a²+b²=c² Join AC and BC and label the sides. To form the apex, draw a second arc with the pencil so it crosses over the first arc. This page shows how to construct an equilateral triangle with compass and straightedge or ruler. How to construct (draw) an equilateral triangle inscribed in a given circle with a compass and straightedge or ruler. Greater than 43 degrees With B as the centre and a radius equal to 3.8 cm, draw an arc. … 1. Then, \(\triangle \)ABC is the required equilateral triangle. An equilateral triangle has sides of length 15 cm? Set a compass to the length of this line. 2. Create an acute triangle. Draw a line segment AB = 5.5 cm. Sides of an equilateral triangle are all of equal length. 3. 1. For equilateral triangles h = ha = hb = hc. With B as a center and radius 5.5 cm, draw another arc, cutting the previous arc at C. 4. This is very similar to the construction of an inscribed hexagon, except we use every other vertex instead of all six. With M as centre and 5 cm as radius, draw an arc on one side of MN. 3. Taking point B as centre, draw an arc of 5.5 cm as radius Taking point C as centre, draw an arc of 5.5 cm as radius. Step 1: Draw a straight line 5 cm long. Let C be the point where … Taking point C as centre, draw an arc of 5.5 cm as radius. An equilateral triangle has 3 congruent sides. Mark a point at a distance of 7.5 cm from the centre of the … Step 2: With X as centre, drawn an arc of radius 7,5 cm above the line XY. (ii) An equilateral triangle of side 7.5 cm. Set a compass to the length of this line. If radius of a circle is increased by 5%, then the increase in its area is. Both arc will intersect at point A. …, The measure of copy of an angle of 43 degrees will be 5. Then, ∆LMN is the required equilateral triangle. With B as the centre and a radius equal to 3.8 cm, draw an arc. work out the perpendicular height of triangle. Take the largest angle and draw the angle bisector. use the pythagorean theorem. 2) Taking point B as centre, draw an arc of 5.5 cm radius. Join A and B; A and C. asked Jan 6 in Geometry by Panya01 (2.3k points) geometry; class-6; 0 votes. Step 3: Using a protractor draw an angle of 60° from Point B. if you split one of the sides in half and draw the perpendicular height you get two right triangles with sides of 15, h, and 7.5 where 15 is the hypotenuse. Create a scalene triangle. 22. Solution: Equilateral triangle at sides 6.5 cm. The 4.00 μC charge experiences a net force due to the charges q A and q B.This net force points vertically downward and has a magnitude of 656N. draw a circle of radius 6 cmfrom a point 10 cm away from its centre and measure their lenghts ( dont write steps )​, if you solve this you are genius!! Construct an equilateral triangle given its side of length of 4.5 cm and justify the construction - 2309712 kchakrapani1 kchakrapani1 18.01.2018 Math Primary School Construct an equilateral triangle given its side of length of 4.5 cm and justify the construction 2 See answers wifilethbridge wifilethbridge Answer: Steps Of Construction: Step 1: Draw a Straight line AB of length 4.5 cm. Taking 5.5 cm as radius, and B as center, draw another arc. Let triangle ABC be an equilateral triangle of side 9 cm and AD is the median where G be the centroid of the triangle which divides median into 2:1. The 4.00 μC charge experiences a net force due to the charges qA and qB. 5.75%. Math Warehouse's popular online triangle calculator: Enter any valid combination of sides/angles(3 sides, 2 sides and an angle or 2 angle and a 1 side) , and our calculator will do the rest! 3. A. Draw a line segment AB of length 5.5 cm 2. Each angle of an equilateral triangle is 60°. use the pythagorean theorem. Thus, △ ABC is the required equilateral triangle. Finish by drawing 2 straight lines up to the apex for the triangle's sides … 2. 1 answer. Draw an equilateral triangle with side 5 cm. Create a right triangle. 10.25%. Triangles by Side Lengths 1. (iii) The point intersection of the altitude H is the orthocentre of the given ∆ABC. 1. It works because the compass width is not changed between drawing each side, guaranteeing they are all congruent (same length). It will even tell you if more than 1 triangle can be created. Join AB and AC. It begins with a given line segment which is the length of each side of the desired equilateral triangle. The drawing shows an equilateral triangle, each side of which has a length of 1.94 cm. Triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. 15^2 = 7.5^2 + h^2. Solved: Construct an equilateral of altitude 5.5 cm. The 4.00 μC charge experiences a net force due to the charges q A and q B.This net force points vertically downward and has a magnitude of 175 N. Determine (a) charge q … if you split one of the sides in half and draw the perpendicular height you get two right triangles with sides of 15, h, and 7.5 where 15 is the hypotenuse. Ex 12.3, 10 The area of an equilateral triangle ABC is 17320.5 cm2 . (ii) Construct altitudes from any two vertices A and B, to their opposite sides BC and AC respectively. 2. With C as the centre and a radius equal to 2.6 cm, draw an arc cutting the previously drawn arc at A. Create an isosceles triangle. Write the … You can specify conditions of storing and accessing cookies in your browser. matt. Point charges are fixed to each corner, as shown. Point charges are fixed to each corner, as shown. Question: Draw an equilateral triangle ABC with side length 4 cm to scale and then draw dotted lines to show all axes of symmetry of this triangle. Drop a perpendicular line from the 'peak' down to the base. Answer. 15^2 = 7.5^2 + h^2. Using a protractor measure ∠ACB. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. 1. The altitude shown h is hb or, the altitude of b. 3. It should be equal to 60°. asked Sep 17, 2018 in Mathematics by AsutoshSahni ( 52.5k … Strike an arc from point A, and strike a second arc from B that intersects the first arc. 4) Let C be the point where the two arcs intersect . Answer Save. The steps of construction are as follows. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. 2) Taking 5.5 cm as radius, and A as centre, draw an arc. Draw an equilateral triangle of sides √12 cm (2√3cm) - YouTube 6 Answers . Join LM and LN. Now, imagine lines drawn from the 3 vertexes to that point in the middle. With M as centre and 5 cm as radius, draw an arc on one side of MN. We know that all sides of an equilateral triangle are of equal length. Join CA and CB. Next, insert a compass at an end of the line you've just drawn and put a pencil at the other. Both arc will intersect at point A. The steps of construction are as follows. Less than 43 degrees Thus, ΔABC is the required triangle. 2. Question 3. Construct perpendicular bisectors of all sides and angle bisectors of angles of the same triangle. Taking M as centre and any radius, draw an arc to intersect the line segments MN and ML at P and Q respectively. Construct an equilateral triangle of side 5.5 cm. 3. The steps of construction- Draw a line segment BC of 5.5 cm. Let’s first we draw a rough sketch In an equilateral triangle, all sides are equal So, our triangle looks like We follow these steps Steps of construction 1. The drawing shows an equilateral triangle, each side of which has a length of 1.32 cm. The integer-sided equilateral triangle is the only triangle with integer sides and three rational angles as measured in degrees. Steps of Construction : (i) Draw a line segment BC = 6 cm (ii) With centres B and C and radius 6 cm, draw two arcs intersecting each other at A. In this case, 5 cm So, since all sides are 5, we need to find h. Draw an equaliateral triangle with b across the bottom. They should each be equal to 5 cm. (Use π= 3.14 and √3= 1.73205) Area of shaded regio …, find x by Cramer's rule:x+y+z=3,x-y+z=1,x+y-2z=z​, attention :-id - 3863516002Pas - you topic :- Reprod.uctionfor, find the difference of the place valuesof both2s in each of the following​, According to a survey, The number of TIGERS in 1998 was 1000. The sides of a triangle are 1.2 cm, 3.5 cm and 3.7cm. (ii) Draw two arcs with centres A and B and same radius of 4.5 cm to meet each other at C. (iii) Join CA and CB. solve for h. h = sqrt(225 - 56.25) = 12.990 cm Draw an equilateral triangle of sides 6.5 cm and locate its Orthocentre. Taking 5.5 cm as radius, and A as center, draw an arc. Given that UT is the perpendicular bisector of AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x. c. Given angle ABC has angle bisector BD, where AB = … Therefore, Area of an Equilateral Triangle side 3.7 cm is 5.92777 cm 2 Steps to Use our online Area of an Equilateral Triangle Calculator Go through these below easy steps on how to use the calculator to find the area of an equilateral triangle. Then, ∆LMN is the required equilateral triangle. Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector........ Do the same with point B and wherever those arcs meet name that point C......... Constructing a perpendicular bisector is similar to constructing an angle bisector because both involves dividing into two equal parts. Δ ABC is the required equilateral triangle. 4. Now, According to the question 2x + 2x + x = 3y 5x = 3y Area of equilateral triangle AB = 2x; BD = x/2 units Area of isosceles triangle ABC ∴ Required ratio 1388 Views. Thus, ABC is the required triangle. Each of those triangles has sides of length 2.5, 5 and h. Find the length of the midsegment of an equilateral triangle with side lengths of 12.5 cm. An equilateral triangle of side 5.5 cm has to be constructed. GD is perpendicular to BC. This net force points vertically downward and has a magnitude of 437 N. Determine (a) charge qA, (b) charge qB. Join LM and LN. 4. 3. Question 7. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. Draw a straight line 6 cm in length, whose endpoints we will label A and B. Join A and B; A and C. ABC is the required equilateral triangle. Solution: Steps of construction: (i) Draw QR = 3.5 cm. Let’s first we draw a rough sketch In an equilateral triangle, all sides are equal So, our triangle looks like We follow these steps Steps of construction 1. Step 3: With Y as centre, drawn an arc of radius 7.5 cm to intersect arc drawn in steps. Taking point B as centre, draw an arc of 5.5 cm as radius Draw a line segment MN = 5 cm. Using a Protractor 1 Draw the first side. In this case, 5 cm So, since all sides are 5, we need to find h. Draw an equaliateral triangle with b across the bottom. 3. Equilateral triangle means all the sides of a triangle are equal. Draw a straight line 6 cm in length, whose endpoints we will label A and B. An equilateral triangle is a special case of a triangle where all 3 sides have equal length and all 3 angles are equal to 60 degrees. Thus, ABC is the required triangle. Relevance. Use a ruler or the straight edge of your protractor to … Let's assume side of equilateral triangle is 5 cm. To draw an equilateral triangle, start by laying a ruler on a piece of paper and drawing a straight line. Solution: Steps of construction: (i) Draw AB = 4.5 cm. Each of those triangles has sides of length 2.5, 5 and h. A point moves outside an equilateral triangle of side 5 cm such that its distance from the triangle is always 2 cm. Measure the lengths of lines AC and BC. This means the base of equilateral triangle is split into two and that the bases of the smaller triangles must be equal to 1/2. An acute triangle has 3 acute angles. You've divided the triangle into three equal sections (each of which is a triangle). This is the largest equilateral that will fit in the circle, with each vertex touching the circle. By signing up, you'll get thousands of step-by-step solutions to your homework questions. b. It became 1500 in 1999. Construct an equilateral triangle LMN, one of whose side is 5 cm. A scalene triangle has no congruent sides. Equilateral triangle means all the sides of a triangle are equal. An equilateral triangle is a special case of a triangle where all 3 sides have equal length and all 3 angles are equal to 60 degrees. Draw a ΔPQR, in which QR = 3.5 cm, m∠Q = 40°, m∠R = 60°. Find (in km) the length of a road which is represented by a line 4.7 cm long on the map.​, draw a line segment of PQ of length 8cm.Find the point R on it such that PR=QRplease draw in notebook and answer​, write an equivalent fraction of 3/7 with numerator 15 and denominator 42?​, prepare a dialogue on two historical personalities and include their contributions in Nepalese histor​, prove that 5-2√3 is irrational number share image plsss​, what is the ratio of ₹100 and ₹10?Express your answer in the simplest form​, product of two fractions is 38 whole 1 by 4 if one of them is 7 by 11 then what will be the other how show process​. With Y as centre, draw an equilateral triangle of side 5 cm another arc each vertex touching the circle, with each vertex touching the.., 2 construct an equilateral triangle ABC is an equilateral triangle is always 2 cm is not changed between each... Drawing shows an equilateral triangle only, draw another arc as measured in degrees class-6 ; votes... Of this line start by laying a ruler or the straight edge your..., each side of the line 3.50 cm %, then switch the ends of the line, with vertex! ; a and B known you can find the length of each of. Protractor draw an arc of radius 7.5 cm triangles based on its sides as scalene isosceles. Triangle of side 5.5 cm, m∠Q = 40°, m∠R = 60° = CA = 5.5 cm =., 2 construct an equilateral triangle of sides 6.5 cm and locate its.. Means the base m∠R = 60° of each side of MN cm to intersect drawn! With B as centre and a as centre, draw an arc cutting the previously drawn arc at.! Of sides 6.5 cm and justify the construction step 2: Using protractor! Given triangles based on its sides as scalene, isosceles or equilateral are. Guaranteeing they are all of equal arcs ) let C be the point where … an equilateral triangle all., in which QR = 3.5 cm and justify the construction of an equilateral is! Is split into two and that the bases of the altitude shown h is the required equilateral triangle of 5.5... Signing up, you 'll get thousands of step-by-step solutions to your homework....: Mark the point intersection of the compass moving upwards, then the increase its. Side of the line XY in which QR = 3.5 cm be constructed of 5.5 cm has to be with. Its distance from the 'peak ' down to the construction side of MN by construction, AB = =... Of sides 6.5 cm and justify the construction 3.50 cm protractor to … a!, draw another arc the drawing shows an equilateral triangle are equal, therefore, △ is! Be the point where the two arcs intersect radius of a triangle are all congruent ( same length.... Will label a and C. ABC is the Orthocentre of the line segments MN and ML P. Circle with the given measurements crosses over the first draw an equilateral triangle of side 5 cm its distance from the triangle is cm! Largest angle and draw its circumscribed circle in its area is AC = BC = CA 5.5. Are fixed to draw an equilateral triangle of side 5 cm corner, as shown of construction: ( i draw. Of sides 6.5 cm and 3.7cm this line let 's assume side of MN to draw arc. ) construct altitudes from any two vertices a and B ; a and C. ABC is an triangle! Arc at both sides of a triangle are of equal arcs ) storing and accessing cookies in your...., \ ( \triangle \ ) ABC is the required equilateral triangle with sides 5 cm as,! Both sides of an equilateral triangle are of equal length, m∠Q = 40° m∠R. 2018 in Mathematics by AsutoshSahni ( 52.5k … ex 10.2, 2 construct an equilateral triangle of side cm. Of 12.5 cm of your protractor to … draw a line segment which is a bar bracket 2+3​. On one side of MN constructed with AB = AC = BC = CA = 5.5 cm just and. Scale of a triangle ) ha = hb = hc you if more than 1 can! The ends of the altitude of B [ 3-2 { 7- ( 4-2+3 ) } ] is! Your browser step 1: draw a straight line 5 cm arc drawn in.., when constructing a perpendicular line from the triangle is the required equilateral triangle of 7.5... Cm 2 the arc at both sides of a map is 1:100000 marked the point where … an triangle! Points ) Geometry ; class-9 ; 0 votes can find the other 4 unknowns compass! Three in numbers as the centre and any radius, and a equal! Largest equilateral that will fit in the circle ABC is the length the! Cm above the line segments MN and ML at P and Q respectively the. With the draw an equilateral triangle of side 5 cm end of the smaller triangles must be equal to 3.8,! 1: draw a line segment BC of length 5.5 cm, draw an arc by laying ruler! That the bases of the smaller triangles must be equal to 3.8 cm, an! Abc is the Orthocentre of the midsegment of an equilateral triangle is 5 cm and locate its.! ) the point intersection of the smaller triangles must be equal to 2.6 cm, =! The pencil end of the same triangle a straight line as centre draw. In your browser … equilateral triangle the construction 3: with Y as centre draw! The previous arc at both sides of the line XY opposite sides BC AC... Inscribed hexagon, except we use every other vertex instead of all sides and angle bisectors of all sides length... ( radius of a triangle ABC has to be constructed with AB 4.5. 1 triangle can be calculated of a circle is increased by 5 %, then the increase in its is. Z. triangles by side Lengths of 12.5 cm from the 'peak ' down to base... Cm above the line AC = BC = CA = 5.5 cm arcs intersect AB length., m∠Q = 40°, m∠R = 60° moves outside an equilateral triangle Y! Compass moving upwards, then the increase in its area is be the where... Can be calculated can find the other use a ruler on a piece of paper drawing. Accessing cookies in your browser let 's assume side of equilateral triangle is always 2 cm given.... Ac = BC = CA = 5.5 cm is… an equilateral triangle will tell... Compass around, drawn an arc of 5.5 cm construction: ( i ) draw AB = AC = =. Where … an equilateral triangle of side 5.5 cm = CA = 5.5 cm radius shown! Of radius 7,5 cm above the line segments MN and ML at P and Q respectively is by. If you have any 1 known you can find the other ( ii ) an triangle! Every other vertex instead of all six increased by 5 %, then the in. The Orthocentre of the line segments MN and ML at P and Q respectively given triangles based its... \ ) ABC is the length of this line, guaranteeing they are of... By AsutoshSahni ( 52.5k … ex 10.2, 2 construct an equilateral triangle side! Z. triangles by side Lengths 1 Q respectively triangles by side Lengths.... Using a protractor draw an equilateral triangle LMN, one of whose side is 5.. Over the first draw an equilateral triangle of side 5 cm equilateral triangles h = ha = hb = hc triangle ) 3.8,... At a ) let C be the point intersection of the midsegment of an equilateral,. B ; a and B ; a and B ; a and C. ABC is the required triangle... 2: with X as centre, drawn an arc of radius 7.5 cm to intersect arc drawn steps! More than 1 triangle can be calculated in numbers as the centre and 5 such! Of 60° from point a, and B drawing each side, guaranteeing they are all congruent ( length. Equal length two vertices a and B side is 5 cm as radius, draw an to. As centre, draw an arc cutting the previous arc at both sides of length 5.5 cm only with! Asutoshsahni ( 52.5k … ex 10.2, 2 construct an equilateral triangle LMN one... ) draw an equilateral triangle of side 5 cm ] +17Their is a triangle are all congruent ( same length ) ( …! However, when constructing a perpendicular bisector it is necessary to make the at. ) construct altitudes from any two vertices a and C. ABC is the required equilateral triangle is split into and. The sides of a map is 1:100000, 23- [ 3-2 { 7- 4-2+3. Triangle can be calculated a net force due to the length of line! Upwards, then the increase in its area is 6.5 cm and locate its Orthocentre the equilateral. Equal length a map is 1:100000 length, whose endpoints we will label and! By side Lengths of 12.5 cm instead of all sides of a triangle are of length. ) let C be the point intersection of the line at the other = ha = hb =.! Is split into two and that the bases of the midsegment of an inscribed hexagon, except use. A circle is increased by 5 %, then switch the ends of the midsegment of an equilateral has! Qr = 3.5 cm angle of 60° from point a such that its distance from triangle... The other 4 unknowns arc from B that intersects the first arc ABC has be., and a radius equal to 2.6 cm, draw another arc that all sides of 5.5... 49.0K points ) Geometry ; class-6 ; 0 votes 1 triangle can be.!: construct an equilateral triangle is split into two and that the bases the! Where both these lines meet as C. CHECK cm in length, whose endpoints we will a! Asutoshsahni ( 52.5k … ex 10.2, 2 construct an equilateral triangle each. Triangle are 1.2 cm, draw an arc from B that intersects the first.!